Question

An object is taken to height 2R above the surface of earth , the increase in potential energy is

[R is radius of earth]

• A. $\frac{mgR}{2}$
• B. $\frac{mgR}{3}$
• C. $\frac{2mgR}{3}$
• D. 2 mgR

Answer 1

The correct option is A $\frac{mgR}{2}$

$\Delta U=GMm[\frac{1}{R_2}-\frac{1}{R_1}]$

Here, $R_1=R;R_2=2R$

$\therefore \Delta U=\frac{GMm}{2R}=\frac{gmR}{2}\to$ Gain in potential.