An object is thrown along a direction inclined at an angle of $45^{o}$ with the horizontal direction. The horizontal range of the particle is equal to

Vertical height

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Twice the vertical height

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Thrice the vertical height

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Four times the vertical height

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Solution

The correct option is D Four times the vertical height
We know that , for the calculation of vertical height
$H = \frac{v_{0}^{2} sin 45 ° R}{2 g} R = 4 H = 4$ (The vertical height)
$∴$ D is the correct answer.

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An object is thrown along a direction inclined at an angle of 45o with the horizontal direction. The horizontal range of the particle is equal to

The correct option is D Four times the vertical heightWe know that , for the calculation of vertical heightH=v20sin45°R2gR=4H=4 (The vertical height)∴ D is the correct answer.

An object is thrown along a direction inclined at an angle of $45^{o}$ with the horizontal direction. The horizontal range of the particle is equal to

The correct option is D Four times the vertical height
We know that , for the calculation of vertical height
$H = \frac{v_{0}^{2} sin 45 ° R}{2 g} R = 4 H = 4$ (The vertical height)
$∴$ D is the correct answer.