Question

An object is thrown at an angle of ${60}^{\circ }$ with the horizontal with kinetic energy K. What will be its kinetic energy at highest point?

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

The kinetic energy of the projectile is given by,

$\frac{1}{2}$ m $v^2$

Since the horizontal component of velocity (v=ucos\theta) remains a constant and the vertical component of velocity becomes zero at the highest point,

$\frac{1}{2}$ m $u^2$ ${cos\theta }^2$