An object is thrown up with a speed of 50m/s. Its height from the ground after 7 s is ( take g =10m/s^2)

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Solution

Given,
Speed of object thrown above , u = 50m/s
Time , t = 7sec
Let object reach h hight in 7 sec from the ground ,when we thrown it with speed 50m/s .

Use formula,
S = ut + 1/2at²
here , s = h , a = -g and t = 7sec
Now, h = 50 × 7 - 1/2 × 10 × (7)²
= 350m - 245m
= 105m

Hence, height is 105m

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