Derivation of Velocity-Time Relation by Graphical Method
An object is ...
Question
An object is thrown vertically upward with a speed of 30m/s. The velocity of the object half a second before it reaches the maximum height is
A
4.9m/s
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B
9.8m/s
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C
19.6m/s
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D
25.1m/s
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Solution
The correct option is A4.9m/s Velocity half second before maximum height= Velocity half second after maximum height (Return journey) For downward journey : Initial velocity u=0m/s We have g=9.8m/s2 Time t=12s Thus velocity after half second v=u+gt v=0+9.8×12=4.9m/s