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Question

An object is thrown vertically upward with a speed of 30m/s. The velocity of the object half a second before it reaches the maximum height is

A
4.9m/s
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B
9.8m/s
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C
19.6m/s
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D
25.1m/s
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Solution

The correct option is A 4.9m/s
Velocity half second before maximum height = Velocity half second after maximum height (Return journey)
For downward journey :
Initial velocity u=0 m/s
We have g=9.8 m/s2
Time t=12 s
Thus velocity after half second v=u+gt
v=0+9.8×12=4.9m/s

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