An object is thrown vertically upwards with a velocity is \mu, the greatest height It to which it will rise before falling back is given by : (a) μ/g (b) μ2/2g (c) μ2/g (d) μ/2g
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Solution
A body is thrown vertically upward . at maximum height velocity of body = 0 use kinematics formula , v² = u² + 2as
here v = 0 a = -g s = H
0 = u² -2gH
H = u²/2g hence, maximum height attained by body u²/2g option ( b) is correct