An object is thrown vertically upwards with a velocity u, the greatest height h to which it will rise before falling back is given by :

(a) u/g
(b) u²/2g
(c) u²/g
(d) u/2g

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Solution

(b) u² / 2g
At the maximum height 'h', the velocity becomes zero.
Using,
v^2 = u^2 − 2gh
⇒ 0 = u^2 − 2gh
⇒ h = u^2/(2g)

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An object is thrown vertically upwards with a velocity u, the greatest height h to which it will rise before falling back is given by : (a) u/g (b) u2/2g (c) u2/g (d) u/2g

(b) u2 / 2g At the maximum height 'h', the velocity becomes zero. Using, v^2 = u^2 − 2gh ⇒ 0 = u^2 − 2gh ⇒ h = u^2/(2g)

An object is thrown vertically upwards with a velocity u, the greatest height h to which it will rise before falling back is given by :

(a) u/g
(b) u²/2g
(c) u²/g
(d) u/2g

(b) u² / 2g
At the maximum height 'h', the velocity becomes zero.
Using,
v^2 = u^2 − 2gh
⇒ 0 = u^2 − 2gh
⇒ h = u^2/(2g)