An object is thrown verticlly upwards to a height of 10m. Calculate its velocity with which it was thrown upwards and time taken by it to reach the height of 10m.

Open in App

Solution

Let velocity of object is u
we know, at 10m height object will be rest .
so, final velocity = 0

A/C to kinematics equations,
v² = u² + 2aS
0 = u² +2(-g) × 10
0 = u² - 2 × 100
u² = 200
u = 10√2 m/s

Time taken by the object to reach the highest point is t

heighest point here is 10m so the equation below is applicable
v = u + at
0 = 10√2 - 10t
t = 10√2/10 sec
t = √2 sec

Suggest Corrections

Similar questions

An object is thrown vertically upwards and rises to a height of $10 c m$ . Calculate
(i) the velocity with which the object was thrown upwards and
(ii) the time taken by the object to reach the highest point.

Q. An object is thrown vertically upwards and rises to a height of 10 m. Calculate the velocity with which the object was thrown upwards :

Q. An object thrown vertically upwards, rises to a maximum height of

10 m

. What is the velocity with which it is thrown upwards? (Take

g = 9.8 m s^{- 2}

)

Q. An object thrown vertically upwards reaches a height of

500 m

. What was its initial velocity? How long will the object take to come back to the earth? Assume

g = 10 m / s^{2}

A body is thrown vertically upwards and rises to a height of 10m. The velocity with which the body was thrown upwards is : (g = 9.8 $m / s^{2}$ )

Join BYJU'S Learning Program