An object is tossed vertically into the air with an initial velocity of $8 m/s$ . Using the sign convertion upwards as positive, how does the vertical component of the acceleration $a_{y}$ of the object (after leaving the hand) vary during the flight of the object?

On the way up a_{y} > 0, on the way down a_{y} > 0

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On the way up a_{y} < 0, on the way down a_{y} > 0

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On the way up a_{y} > 0, on the way down a_{y} < 0

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On the way up a_{y} < 0, on the way down a_{y} < 0

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Solution

The correct option is D $On the way up a_{y} < 0, on the way down a_{y} < 0$
Acceleration due to gravity acts down ward irrespective of direction of motion.
As per sign convention upwards is positive.
So, $a_{y} < 0.$

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