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Question

An object lying at the equator of the earth will fly off the surface (will feel weightlessness), if the length of the day becomes

A
1.00h
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B
1.41h
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C
17.0h
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D
17.0min
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Solution

The correct option is A 1.00h
Escape velocity at earth radius R is given by V=2GMR=2gR
Now, time period T=2πR2gR=π2Rg=3.14×2×6.4×1069.8=1 hr(approx.)
A is the right answer.

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