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Standard X

Mathematics

Average(Mean)

An object mov...

Question

An object moves $18 m$ in the first $3 s, 22 m$ in the next $3 s$ and $14 m$ in the last $3 s$ . What is its average speed?

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Solution

We know that the,

Avg speed is equal to the total distance divided by the total time taken,

avg speed $= \frac{18 + 22 + 14}{3 + 3 + 3} = \frac{54}{9} = 6 m / s$

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Similar questions

Solve the following examples.

a) An object moves 18 m in the first 3 s, 22 m in the next 3 s and 14 m in the last 3 s. What is its average speed?

b) An object of mass 16 kg is moving with an acceleration of 3 m/s² . Calculate the applied force. If the same force is applied on an object of mass 24 kg, how much will be the acceleration?

c) A bullet having a mass of 10 g and moving with a speed of 1.5 m/s, penetrates a thick wooden plank of mass 90 g. The plank was initially at rest. The bullet gets embedded in the plank and both move together. Determine their velocity.

d) A person swims 100 m in the first 40 s, 80 m in the next 40 s and 45 m in the last 20 s. What is the average speed?

(1) An object moves 18 m the in first 3 second and 22 m in the next 3 second while it travels 14 m in the last 3 second. Calculate average speed. [Ans = 6 m/s]

(2) A person travels a distance of 72 km in 4 hours. Calculate average speed in m/s.

[Ans = 5 m/s]

Q. An object moves

18 m

in the first

3

seconds and

22

m in the next

3

seconds while it travels

14 m

in the last

3

seconds. Calculate average speed in m/s.

Q. A particle moves according to the equation

x = 2 t^{2} - 5 t + 6

. The average velocity in the first

3 s

and velocity at

t = 3 s

are repectively.

Q. A particle moving with a non-zero velocity and constant acceleration on straight line travels

15 m

in first

3 s

and

33 m

in next

3 s

in the same direction, find
(i) initial velocity of particle
(ii) acceleration of particle

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An object moves 18m in the first 3s,22m in the next 3s and 14m in the last 3s. What is its average speed?

We know that the,Avg speed is equal to the total distance divided by the total time taken,avg speed =18+22+143+3+3=549=6 m/s

An object moves $18 m$ in the first $3 s, 22 m$ in the next $3 s$ and $14 m$ in the last $3 s$ . What is its average speed?

We know that the,

Avg speed is equal to the total distance divided by the total time taken,

avg speed $= \frac{18 + 22 + 14}{3 + 3 + 3} = \frac{54}{9} = 6 m / s$