An object moves at a constant speed along a circular path in a horizontal XY plane. With the center at the origin. When the object is at x=−2m, its velocity is −(4m/s)^j. What is the object's acceleration when it is y=2m:
A
−(8m/s2)^j
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B
(8m/s2)^i
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C
−(4m/s2)^j
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D
(4m/s2)^i
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Solution
The correct option is A−(8m/s2)^j Velocity , v=−(4m/s)^j