An object moves from infinity towards convex lens. Comment on change in magnitude of magnification.

It increases from

0 t o \infty

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It increases from

0 t o \infty

and then reduces from

\infty t o 1

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It increases from

0 t o \infty

and then reduces from

\infty t o 0

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It decreases from

\infty t o 0

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Solution

The correct option is B It increases from $0 t o \infty$ and then reduces from $\infty t o 1$
Position of object Magnification(m)
Infinity m=0
Beyond $2 F_{1}$ -1<m<0
At $2 F_{1}$ m=-1
Between $F_{1}$ & $2 F_{1}$ m<-1
At $F_{1}$ m= $- \infty$
Between lens and $F_{1}$ m>1
(closer to 1 when object is closer to mirror)

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Position of object	Magnification(m)
Infinity	m=0
Beyond $2 F_{1}$	-1<m<0
At $2 F_{1}$	m=-1
Between $F_{1}$ & $2 F_{1}$	m<-1
At $F_{1}$	m= $- \infty$
Between lens and $F_{1}$	m>1 (closer to 1 when object is closer to mirror)

An object moves from infinity towards convex lens. Comment on change in magnitude of magnification.

The correct option is B It increases from 0to∞ and then reduces from ∞to1 Position of object Magnification(m) Infinitym=0 Beyond 2F1 -1<m<0 At 2F1 m=-1 Between F1 & 2F1 m<-1 At F1 m=−∞ Between lens and F1 m>1(closer to 1 when object is closer to mirror)