An object of $40 k g$ mass is moving with velocity $2 m / s$ . A force applied on it increases its velocity to $5 m / s$ . Find the work done by force.

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Solution

Work done can be calculated as follows:
$W = △ K . E$
$W = \frac{1}{2} m (v^{2} - u^{2})$
$= \frac{1}{2} \times 40 (5^{2} - 2^{2})$
$= 20 (5 + 2) (5 - 2)$
$= 20 \times 7 \times 3 = 420 J$

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An object of 40kg mass is moving with velocity 2m/s. A force applied on it increases its velocity to 5m/s. Find the work done by force.

Work done can be calculated as follows:W=△K.EW=12m(v2−u2) =12×40(52−22) =20(5+2)(5−2) =20×7×3=420J

An object of $40 k g$ mass is moving with velocity $2 m / s$ . A force applied on it increases its velocity to $5 m / s$ . Find the work done by force.

Work done can be calculated as follows:
$W = △ K . E$
$W = \frac{1}{2} m (v^{2} - u^{2})$
$= \frac{1}{2} \times 40 (5^{2} - 2^{2})$
$= 20 (5 + 2) (5 - 2)$
$= 20 \times 7 \times 3 = 420 J$