An object of height 2 cm is placed at a distance of 15 CM in front of concave lens of power -100 . Find the size of the image

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Solution

Here,
h = 2 cm

u = – 15 cm

Also,

Power of the lens = – 10 D.

Therefore, Focal length = – 100/10 cm

➡ – 10 cm.

Now, using lens formula, we get

➡ –1/10 = 1/15 + 1/v

➡ 1/v = –1/10 – 1/15

➡ 1/v = –1/6

➡ v = – 6 cm.

Now, using

➡ h' = v/u × h, we get

➡ h' = –6/(–15) × 2

➡ h' = 0.8 cm

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