An object of height 5 cm is placed in front of a mirror. The mirror forms an inverted image of height 10 cm. Calculate the magnification.

+½

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-½

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-2

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Solution

The correct option is D -2
Using the sign conventions,
Height of object, h = 5 cm (upright)
Height of image, h’ = -10 cm (inverted)
Now, from the magnification formula,
$m = \frac{h^{'}}{h}$
$m = \frac{(- 10)}{(5)} = - 2$

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An object of height 5 cm is placed in front of a mirror. The mirror forms an inverted image of height 10 cm. Calculate the magnification.

The correct option is D -2Using the sign conventions, Height of object, h = 5 cm (upright) Height of image, h’ = -10 cm (inverted) Now, from the magnification formula, m=h′h m=(−10)(5)=−2

The correct option is D -2
Using the sign conventions,
Height of object, h = 5 cm (upright)
Height of image, h’ = -10 cm (inverted)
Now, from the magnification formula,
$m = \frac{h^{'}}{h}$
$m = \frac{(- 10)}{(5)} = - 2$