An object of height 5cm is placed at a distance of 10cm from a convex mirror of radius of curvature 30cm.Find the nature and position and size of the image?
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Solution
Hey!! Given mirror is convex mirror Thus f = R/2 = 30/2 = 15cm u = -10cm h = 5cm Now we have to find the nature, position and size of image
Thus using mirror equation 1/f = 1/u + 1/v => 1/v = 1/f -1/u =>1/v = 1/15+1/10 => 1/v = 25/150 => v = 6 cm { hence image will be formed between focus and pole .
Now magnification m = -(v/u) = (h'/h) m = -(-6/10) = 3/5 { it means that the image will be virtual , react and diminished.
Now again m = h'/h
3/5 = h'/5 => h' = 3cm hence the size of image will be 3cm
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