An object of height 7 cm is kept at a distance of 25 CM in front of a concave mirror . The focal length of the mirror is 15 cm. At what distance from the mirror should a screen be kept so as to get a clear image? What will be the size and nature of image
1/f=1/v+1/u
V is object distance and u is image distance.
F is the focal length.
Substituting the values :1/15=1/25+1/u
1/u=1/15-1/25=5-3/75=2/75
U=75/2=37.5cm
We use the object distance and the image distance to get the magnification.
M=37.5/25=×1.5
The image size =1.5×7=10.5cm
The image is real.