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Question

An object of height 7 cm is kept at a distance of 25 cm in front of a concave mirror. The focal length of the mirror is 15 cm. At what distance from the mirror should a screen be kept so as to get a clear image? What will be the size and nature of the image

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Solution

Object size (h1) = 7 cm
Object distance (u) = -25 cm
Focal length (f) = -15cm
To find: Image distance (v) = ?
Image size (h2) = ?
formula:
1v+1u=1fM =h2h1=vusolution:1v+1u=1f1v=1f1u1v=1151251v=115+1251v=5+375v=752v=37.5 c.mThe screen should be kept 37.5 c.m in front of the mirror. The image is real.M =h2h1=vu h2 =v×h1u h2 =(75)×72×25 h2 =212 h2 =10.5 c.mThe height of the image is 10.5 cm, it is an inverted and enlarged image.

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