An object of mass $0.5$ kg attached to a rod of length $0.5$ m is whirled in a vertical circle at constant angular speed. If the maximum tension in the string is $5$ kg wt., Calculate
(i) speed of stone
(ii) maximum number of revolutions it can complete in a minute.

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Solution

$\begin{matrix} 1 r p m = \frac{2 π}{60} r a d / s e c 1 r a d / s e c = \frac{60}{2 π} r p m 13 .28 r a d / s e c = \frac{60}{2 π} \times 13.28 r p m = 126 .7 r p m \end{matrix}$

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An object of mass 0.5 kg attached to a rod of length 0.5 m is whirled in a vertical circle at constant angular speed. If the maximum tension in the string is 5 kg wt., Calculate (i) speed of stone (ii) maximum number of revolutions it can complete in a minute.

1rpm=2π60rad/sec1rad/sec=602πrpm13.28rad/sec=602π×13.28rpm=126.7rpm

An object of mass $0.5$ kg attached to a rod of length $0.5$ m is whirled in a vertical circle at constant angular speed. If the maximum tension in the string is $5$ kg wt., Calculate
(i) speed of stone
(ii) maximum number of revolutions it can complete in a minute.

$\begin{matrix} 1 r p m = \frac{2 π}{60} r a d / s e c 1 r a d / s e c = \frac{60}{2 π} r p m 13 .28 r a d / s e c = \frac{60}{2 π} \times 13.28 r p m = 126 .7 r p m \end{matrix}$