An object of mass 1 kg has a P.E. of 1 J relative to the ground when it is at a height of :
[Take g = 9.8 $m / s^{2}$ ]

0.102 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9.8m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

32m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 0.102 m
Potential energy(P.E) = mgh
1 = 1 $$ 9.8 $$ h
By solving, h = $\frac{1}{9.8}$

h = 0.102 m or 10 cm

Suggest Corrections

Similar questions

1 k g

1 J

An object of mass 1kg has a potential energy of 10J. What is the height of the object relative to the ground? $(T a k e g = 10 m / s e c^{2})$

1 k g

2 J

= 10 m s^{- 2}

s^{2}

Join BYJU'S Learning Program