An object of mass $1 k g$ is moving at a speed of $10 m s^{- 1}$ . Constant force acts on the object for $4 s$ and changes the speed of object to $2 m s^{- 1}$ in the opposite direction. Choose the correct options:

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-3N

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30N

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-30N

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Solution

The correct options are
A
3N

D
-30N

Given: Initial velocity, $u = 10 m s^{- 1}$ , final velocity $v = - 2 m s^{- 1}$ (The negative sign indicates that final velocity is opposite to the direction of the initial velocity) and time, $t = 4 s$ .

Using the first equation of motion:
$v = u + a t \Rightarrow a = \frac{v - u}{t} = \frac{- 2 - 10}{4}$
$\Rightarrow a = - 3 m s^{- 2}$

Using Newton's second law of motion:
$F = m \times a = 1 \times (- 3) = - 3 Newtons$
Therefore, the magnitude of force is 3N, and the negative sign indicates that the direction of force is opposite to that of initial velocity.

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