An object of mass $1 k g$ moving on a horizontal surface with initial velocity $8 m / s$ comes to rest after $10 s$ . If one wants to keep the object moving on the same surface with velocity $8 m / s$ the force required is

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Solution

Acceleration of the object $= \frac{v - u}{t} = \frac{0 - 8}{10} = - 0.8 m / s^{2}$
So, Friction force $= m a = 0.8 N$
To keep the object moving on the same surface with same velocity, Applied Foce = Frictional Force
$\Rightarrow$ Required Force = $0.8 N$

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An object of mass 1 kg moving on a horizontal surface with initial velocity 8 m/s comes to rest after 10 s. If one wants to keep the object moving on the same surface with velocity 8 m/s the force required is

Acceleration of the object =v−ut=0−810=−0.8m/s2So, Friction force =ma=0.8NTo keep the object moving on the same surface with same velocity, Applied Foce = Frictional Force⇒ Required Force = 0.8N

An object of mass $1 k g$ moving on a horizontal surface with initial velocity $8 m / s$ comes to rest after $10 s$ . If one wants to keep the object moving on the same surface with velocity $8 m / s$ the force required is

Acceleration of the object $= \frac{v - u}{t} = \frac{0 - 8}{10} = - 0.8 m / s^{2}$
So, Friction force $= m a = 0.8 N$
To keep the object moving on the same surface with same velocity, Applied Foce = Frictional Force
$\Rightarrow$ Required Force = $0.8 N$