An object of mass $1 k g$ was moving at a speed of $10 m s^{- 1}$ . A constant force acts for $4 s$ on the object and the speed of object becomes $2 m s^{- 1}$ in opposite direction after the application of force. The force acting on the object have:

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-3N

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30N

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-30N

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Solution

The correct options are
A
3N

D
-30N

Initial velocity $u = 10 m s^{- 1}$
Final velocity $v = - 2 m s^{- 1}$ (since this velocity is in opposite direction of the initial velocity which is taken as positive)
$t = 4 s$
$a = \frac{v - u}{t} \Rightarrow a = \frac{- 2 - 10}{4} \Rightarrow a = \frac{- 12}{4} = - 3 m s^{- 2} F = m \times a \Rightarrow F = 1 \times (- 3) = - 3 Newtons$
Here the minus sign indicates that the direction of force was opposite to the direction of initial velocity. Also, the magnitude of force was 3N (magnitude is the absolute value).

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Q. An object of mass

10 k g

moves at a constant speed of

10 m s^{- 1}

. A constant force that acts for

4 s

on the object gives it a speed of

2 m s^{- 1}

in the opposite direction. The magnitude of force acting on the object is (Take the direction of initial velocity as positive)

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An object of mass $1 k g$ was moving at a speed of $10 m s^{- 1}$ . A constant force acts for $4 s$ on the object and the speed of object becomes $2 m s^{- 1}$ in opposite direction after the application of force. The force acting on the object have: