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Question

An object of mass 1 kg was moving at a speed of 10 m/s. Constant force acts for 4 s on the object and the speed of object was 2 m/s in opposite direction after the applied force was removed. Identify the correct statements.


A

3N

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B

-3N

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C

30N

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D

-30N

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Solution

The correct options are
A

3N


D

-30N


Initial velocity u= 10m/s
Final velocity v= -2 m/s (since this velocity is in opposite direction of the initial velocity which is taken as positive)
t = 4 s
a=vuta=2104a=124=3m/s2F=m×aF=1×(3)=3 newtons
Here the minus sign indicates that the direction of force was opposite to the direction of initial velocity. Also, the magnitude of force was 3 N (magnitude is the absolute value).


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