An object of mass 1 kg was moving at a speed of 10 m/s. Constant force acts for 4 s on the object and the speed of object was 2 m/s in opposite direction after the applied force was removed. Identify the correct statements.
3N
-30N
Initial velocity u= 10m/s
Final velocity v= -2 m/s (since this velocity is in opposite direction of the initial velocity which is taken as positive)
t = 4 s
a=v−ut⇒a=−2−104⇒a=−124=−3m/s2F=m×a⇒F=1×(−3)=−3 newtons
Here the minus sign indicates that the direction of force was opposite to the direction of initial velocity. Also, the magnitude of force was 3 N (magnitude is the absolute value).