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Question

# An object of mass 1 kg was moving at a speed of 10 m/s. A constant force acts on the object for 4s and the object moved with a speed of 2 m/s in opposite direction. The force acting on the object was ___ .

A

3N

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B

-3N

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C

30N

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D

-30N

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Solution

## The correct options are A 3N D -30NInitial velocity u= 10m/s Final velocity v= -2 m/s (since this velocity is in opposite direction of the initial velocity which is taken as positive) t= 4s a=v−ut⇒a=−2−104⇒a=−124=−3m/s2F=m×a⇒F=1×(−3)=−3 Newtons Here the minus sign indicates that the direction of force was opposite to the direction of initial velocity. Also, the magnitude of force was 3N (magnitude is the absolute value).

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