An object of mass $10 k g$ is taken from point A to point B along the circumference of a vertical circle of radius $5 m$ . What is the work done by the gravity? (Take g = $10 m / s^{2}$ )

500 J

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- 1000 J

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1000 J

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1500 J

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Solution

The correct option is B $- 1000 J$
Given,
Mass $m = 10 k g$ ,
Radius $r = 5 m$ ,
Displacement from A to B $S$ = $10 m$
Gravitational force $F$ = $m g$ = $100 N$
Work done = $F \times S \times c o s θ$
The angle between the force and the displacement = $180^{\circ}$
Work done = $100 \times 10 \times c o s 180^{\circ}$ = $- 1000 J$
Work done by gravity = $- 1000 J$

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An object of mass 10 kg is taken from point A to point B along the circumference of a vertical circle of radius 5 m. What is the work done by the gravity? (Take g = 10 m/s2)

The correct option is B −1000 JGiven, Mass m=10 kg, Radius r=5 m, Displacement from A to B S = 10 m Gravitational force F = mg = 100 N Work done = F×S×cosθ The angle between the force and the displacement = 180∘ Work done = 100×10×cos180∘ = −1000 J Work done by gravity = −1000 J

An object of mass $10 k g$ is taken from point A to point B along the circumference of a vertical circle of radius $5 m$ . What is the work done by the gravity? (Take g = $10 m / s^{2}$ )