An object of mass 15 Kg is at a certain height above the ground. If the gravitational P.E. is 480 J, find the height( in meter) at which the object is w.r.t the ground(g=10m/s²)

Open in App

Solution

Law of conservation of energy states that.

Total energy will be constant;

Potential energy = mgh =1510h = 480;

H = 3.2 m

Suggest Corrections

Similar questions

An object of mass 20 kg is raised to a height 5 m above the ground. What is its P.E.? If object is allowed to fall, find its K.E. just before touching the ground and also its K.E. when it is half way down. [3 MARKS]

Q. Find the gravitational potential energy of a

1 k g

mass kept at a height of

5 m

above the ground if

g = 10 m s^{- 2}

Q. An object of mass 1 kg has a P.E. of 1 J relative to the ground when it is at a height of :

[Take g = 9.8

m / s^{2}

]

Q. An object of mass

1 k g

has a P.E. of

1 J

relative to the ground when it is at a height of

Q. A balloon is released from the ground

(h = 0 m)

from rest and starts accelerating with acceleration

5 {m/s}^{2}

vertically upwards. An object is dropped from the balloon, when it is at height

10 m

from the ground. If the balloon is released at

t = 0 sec

, then find the time when the object reaches the ground. Take

g = 10 {m/s}^{2}

Join BYJU'S Learning Program

An object of mass 15 Kg is at a certain height above the ground. If the gravitational P.E. is 480 J, find the height( in meter) at which the object is w.r.t the ground(g=10m/s2)

Law of conservation of energy states that. Total energy will be constant; Potential energy = mgh =15*10*h = 480; H = 3.2 m

An object of mass 15 Kg is at a certain height above the ground. If the gravitational P.E. is 480 J, find the height( in meter) at which the object is w.r.t the ground(g=10m/s²)

Law of conservation of energy states that.

Total energy will be constant;

Potential energy = mgh =1510h = 480;

H = 3.2 m