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Question

An object of mass 2 kg at rest an origin starts moving under the action of a force
F=(3t2^i+4t^j)N
The velocity of the object at t=2 s will be ?

A
(3^i+2^j)m/s
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B
(2^i+4^j)m/s
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C
(4^i+4^j)m/s
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D
(3^i4^j)m/s
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Solution

The correct option is C (4^i+4^j)m/s
Given data
M=2kg
F=(3t2i+4tj)N
we know that F=ma
=mdvdt[a=dvdt]
integrating on both side
Fdt=mdu
Fdt=mv
(3t2i+4tj)dt=2v
3t3i3+4t22j=2v
t3i+2t2j=2v
substituting t22
8i+8j=2v
v=(4i+4j)m/s
AnswerisC

1185821_1038835_ans_da298cd7de504200b306fb0c89debcd1.JPG

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