Question

An object of mass 2 kg is dropped from a height of 10m.What will be its kinetic energy as it reaches the ground?

Answer 1

Dear student

$$\begin{gathered} Whenthebodyisdroppedfromaheighththanonreachinggroundallitspotentialenergyisconvertedintokineticenergy. \\ mgh=\frac{1}{2}m{v}^2 \\ gh=\frac{1}{2}{v}^2 \\ v=\sqrt{2gh}=\sqrt{2g\times 10}=\sqrt{2\times 9.8\times 10}=\sqrt{98\times 2}=14m/s \\ Regards \end{gathered}$$