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Standard XII

Physics

Static Friction

An object of ...

Question

An object of mass $2 k g$ is placed in a frame $(s_{1})$ moving with velocity $10 \to i + 5 \to j m / s$ and having acceleration $5 \to i + 10 \to j m / s^{2}$ . This object is also seen by an observer standing in frame $(s_{2})$ moving with velocity $5 \to i + 10 \to j m / s$ . The net force acting on object with respect to $s_{2}$ frame is

- 10 \to i - 20 \to j N

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10 \to i + 20 \to j N

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- 5 \to i + 10 \to j N

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Zero

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Solution

The correct option is B $10 \to i + 20 \to j N$
Given,

Observer frame have no acceleration

Relative acceleration of object with respect to observer, $a_{r} = (5^i + 10^j) - 0 = (5^i + 10^j) m s^{- 2}$

Force, $\to F = m a s s \times a_{r} = 2 \times (5^i + 10^j) = (10^i + 20^j) N$

Hence, net force on object is $(10^i + 20^j) N$ .

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An object of mass 2 kg is placed in a frame (s1) moving with velocity 10→i+5→jm/s and having acceleration 5→i+10→jm/s2. This object is also seen by an observer standing in frame (s2) moving with velocity 5→i+10→jm/s. The net force acting on object with respect to s2 frame is

The correct option is B 10→i+20→jNGiven, Observer frame have no acceleration Relative acceleration of object with respect to observer,ar=(5^i+10^j)−0=(5^i+10^j)ms−2 Force, →F=mass×ar=2×(5^i+10^j)=(10^i+20^j)N Hence, net force on object is (10^i+20^j)N .