An object of mass 2 kg is placed in a frame (s1) moving with velocity 10→i+5→jm/s and having acceleration 5→i+10→jm/s2. This object is also seen by an observer standing in frame (s2) moving with velocity 5→i+10→jm/s. The net force acting on object with respect to s2 frame is
Given,
Observer frame have no acceleration
Relative acceleration of object with respect to observer,ar=(5^i+10^j)−0=(5^i+10^j)ms−2
Force, →F=mass×ar=2×(5^i+10^j)=(10^i+20^j)N
Hence, net force on object is (10^i+20^j)N .