An object of mass 3 kg is at rest- Now a force F-6 t 2 - i -2t- j-F is applied to the object- Find the velocity of the object t- 3 sec-

The correct option is A 18∧ i +3∧ j F=6t^2î+2tĵ F_x=6t^2î a_x=63t^2î a_x=2t^2î dv_xdt=2t^2î ∫_0^v_2dv_x=∫_0^32t^2dt V_x ...

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Byju's Answer

Standard XII

Physics

Angular Impulse

An object of ...

Question

An object of mass 3 kg is at rest. Now a force $F = 6 t^{2} \land i + 2 t \land j$ .F is applied to the object. Find the velocity of the object t= 3 sec.

18 \land i + 3 \land j

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18 \land i + 6 \land j

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3 \land i + 18 \land j

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18 \land i + 4 \land j

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Solution

The correct option is A $18 \land i + 3 \land j$
$F = 6 t^{2}^i + 2 t^j$
$F_{x} = 6 t^{2}^i$
$a_{x} = \frac{6}{3} t^{2}^i$
$a_{x} = 2 t^{2}^i$
$\frac{d v_{x}}{d t} = 2 t^{2}^i$
$\int_{0}^{v_{2}} d v_{x} = \int_{0}^{3} 2 t^{2} d t$
$V_{x} = \frac{- 2}{3} t^{3} \int_{0}^{3} = 18 m / s$
$F_{y} = 2 t^j$
$a_{y} = \frac{2}{3} t^j$
$\int_{0}^{v_{y}} d v_{y} = \int_{0}^{3} \frac{2}{3} t d t$
$v_{y} = \frac{t^{2}}{3} \int_{0}^{3} = 3 m / s$
$V_{n e t} = 18^i + 3^j$
Option $(A)$

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An object of mass 3 kg is at rest. Now a force F=6t2∧i+2t∧j.F is applied to the object. Find the velocity of the object t= 3 sec.

The correct option is A 18∧i+3∧jF=6t2^i+2t^jFx=6t2^iax=63t2^iax=2t2^idvxdt=2t2^i∫v20dvx=∫302t2dtVx=−23t3∫30=18 m/sFy=2t^jay=23t^j∫vy0dvy=∫3023t dtvy=t23∫30=3 m/sVnet=18^i+3^jOption (A)

An object of mass 3 kg is at rest. Now a force $F = 6 t^{2} \land i + 2 t \land j$ .F is applied to the object. Find the velocity of the object t= 3 sec.