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Oscillations

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Question

An object of mass $400 g r a m s$ is whirled in a horizontal circle of radius $2 m$ . If it performs $60 r . p . m$ , calculate the centripetal force acting on it.

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Solution

$ω = \frac{60 \times 2 π}{60} = 2 π \frac{r a d}{s} ∴ c e n t r i p e t a l f o r c e = m ω^{2} r = (0.4) ({2 π}^{2}) (2) ≃ 31.6 N$

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