An object of mass $40 k g$ having velocity $4 m / s$ collides with another object of mass $60 k g$ having velocity $2 m / s$ . The collision is perfectly inelastic. The loss in energy is:

24 J

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48 J

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72 J

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96 J

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Solution

The correct option is C $48 J$
Mass of first body $m_{1} = 40 k g$ and its velocity $u_{1} = 4 m / s$
Mass of second body $m_{2} = 60 k g$ and its velocity $u_{2} = 2 m / s$
Energy lost in perfectly inelastic collision $Δ K E = \frac{1}{2} \frac{m_{1} m_{2}}{m_{1} + m_{2}} (u_{1} - u_{2})^{2}$
$∴$ $Δ K E = \frac{1}{2} \frac{(40) (60)}{(40 + 60)} (4 - 2)^{2} = 48 J$

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An object of mass 40kg having velocity 4m/s collides with another object of mass 60kg having velocity 2m/s. The collision is perfectly inelastic. The loss in energy is:

The correct option is C 48JMass of first body m1=40 kg and its velocity u1=4 m/sMass of second body m2=60 kg and its velocity u2=2 m/sEnergy lost in perfectly inelastic collision ΔKE=12m1m2m1+m2(u1−u2)2∴ ΔKE=12(40)(60)(40+60)(4−2)2=48 J

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