An object of mass 5 kg falls from rest through a vertical distance of 20 m and reaches a velocity of 10 m/s. How much work is done by the push of the air on the object?
From work energy theorem,
work done by weight + work done by air=ΔKE (change in Kinetic Energy)
Wair=ΔKE−W(weight)
=12mv2−mgh
=12×5×(10)2−5×10×20
=−750J