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Question

An object of mass 5 kg falls from rest through a vertical distance of 20 m and reaches a velocity of 10 m/s. How much work is done by the push of the air on the object?

A
740 J
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B
750 J
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C
760 J
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D
770 J
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Solution

The correct option is B 750 J

From work energy theorem,

work done by weight + work done by air=ΔKE (change in Kinetic Energy)

Wair=ΔKEW(weight)

=12mv2mgh

=12×5×(10)25×10×20

=750J


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