Question

An object of mass $5kg$ is acted upon by a force that varies with position of the object as shown. If the object starts from rest at a point $x=0$. What is its speed at $x=50m$?

Answer 1

$W$=area of $F_S$ graph = $\Delta k$

$(10\times 25)+\frac{1}{2}\times 25\times 10=\frac{1}{2}\times 5\times v^2$

$v=\sqrt{150}=12.2m{s}^{-1}$