Question

An object of mass 5 kg is acted upon by a force that varies with the position of the object. If the object starts out from rest at a point x = 0 and y = 10, and becomes x = 50, when y = 0 [y axis = force in newton and x axis = distance in meter]. What is its speed at x = 25?

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{F}=\mathrm{ma} \\ \mathrm{a}=\frac{\mathrm{F}}{\mathrm{m}} \\ \mathrm{a}=\frac{10}{5}=2\mathrm{m}/{\mathrm{s}}^2 \\ \mathrm{We}\mathrm{know}\mathrm{that}, \\ {\mathrm{v}}^2-{\mathrm{u}}^2=2\mathrm{as} \\ {\mathrm{v}}^2-0=2\times 2\times 25 \\ {\mathrm{v}}^2=100 \\ \mathrm{v}=\sqrt{100}=10\mathrm{m}/\mathrm{s} \end{gathered}$$