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Question

An object of mass 5kgis attached to the hook of a spring balance and the balance is suspended vertically from the roof of a lift. The reading on the spring balance when the lift is going up with an acceleration of 0.25ms-2 is taken, (take,g=10ms-2)


A

51.25N

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B

48.75N

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C

52.75N

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D

47.25N

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E

55N

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Solution

The correct option is A

51.25N


Step 1. Given data:

Gravity,g=10ms-2

Mass,m=5kg

Acceleration,a=0.25ms-2

Step 2. Find weight :

When the lift is going upwards

F=mg+ma

Force will be equal to the weight

W=mg+ma

=m(g+a)

=5(10+0.25)

=51.25N

Hence, (A) is the correct option.


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