An object of mass m has angular acceleration $a = 0.2$ rad $s^{- 2}$ . What is the angular displacement covered by the object after $3$ second? (Assume that the object started with angle zero with zero angular velocity).

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Solution

Given : $α = 0.2 r a d / s$ $t = 3 s$ $w_{i} = 0$
Angular displacement $θ = w_{i} t + \frac{1}{2} α t^{2}$
where $t = 3 s$
So, $θ = 0 + \frac{1}{2} \times 0.2 \times 3^{2} = 0.9 r a d$
$⟹ θ = 0.9 \times \frac{180}{π} = 51^{o}$

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An object of mass m has angular acceleration a=0.2 rad s−2. What is the angular displacement covered by the object after 3 second? (Assume that the object started with angle zero with zero angular velocity).

Given : α=0.2 rad/s t=3 s wi=0Angular displacement θ=wit+12αt2where t=3 sSo, θ=0+12×0.2×32=0.9 rad⟹θ=0.9×180π=51o

An object of mass m has angular acceleration $a = 0.2$ rad $s^{- 2}$ . What is the angular displacement covered by the object after $3$ second? (Assume that the object started with angle zero with zero angular velocity).

Given : $α = 0.2 r a d / s$ $t = 3 s$ $w_{i} = 0$
Angular displacement $θ = w_{i} t + \frac{1}{2} α t^{2}$
where $t = 3 s$
So, $θ = 0 + \frac{1}{2} \times 0.2 \times 3^{2} = 0.9 r a d$
$⟹ θ = 0.9 \times \frac{180}{π} = 51^{o}$