An object of mass m is thrown vertically upwards. At what rate will its momentum change?

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m g^{2}

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\frac{1}{m g^{2}}

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\frac{1}{m g}

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Solution

The correct option is A mg
Gravitational force is acting on the body moving upwards i.e. $F = m g$
Rate of change of momentum of the body is equal to the force acting it.
$⟹ \frac{d p}{d t} = F = m g$

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An object of mass m is thrown vertically upwards. At what rate will its momentum change?

The correct option is A mgGravitational force is acting on the body moving upwards i.e. F=mgRate of change of momentum of the body is equal to the force acting it.⟹ dpdt=F=mg

The correct option is A mg
Gravitational force is acting on the body moving upwards i.e. $F = m g$
Rate of change of momentum of the body is equal to the force acting it.
$⟹ \frac{d p}{d t} = F = m g$