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Question

An object of mass m is tied to a string of length L and a variable horizontal force is applied to it which starts at zero and gradually increases until the string makes an angle θ with the vertical. Work done by the force F is:
1018813_1dcfc309d86648108bc8748415f53ccc.png

A
mgL(1sinθ)
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B
mgL
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C
mgL(1cosθ)
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D
mgL(1+cosθ)
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Solution

The correct option is C mgL(1cosθ)
Applying work energy theorem on object from AB
wall=ΔK

wall=0
wf+wg=0
wf=wg

=(mgh)

wf=mgh

w=mg(LLcosθ)
w=mgL(1cosθ)

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