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Question

An object of uniform density is allowed to float in water kept in a beaker. The object has triangular cross-section as shown in the figure. If the water pressure measured at the three points A,B and C below the object are PA,PB and PC respectively, then:


A
PA>PB>PC
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B
PA>PB<PC
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C
PA=PB=PC
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D
PA=PB<PC
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Solution

The correct option is C PA=PB=PC
As we know, P=ρgh
Hence, at the same vertical height of a static fluid, pressure remains constant (unless fluid is accelerated).

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