An object starting from rest moves on a straight road for time t and comes to rest finally. The distance is converted in two parts. In the first part it is accelerated at constant acceleration α and then decelerated at rate β. Then maximum velocity is
(αβα+β)t
V=(0)+αt1 ........(i)0=(αt1)+βt2 .......(ii)t1+t2=t⇒V=(αβα+β)(t)