An object starts from rest and attains a uniform acceleration of 4 ms−2. What will be its velocity at the end of half a metre?
2 ms−1
Given, acceleration a=4 ms−2, initial velocity u=0 ms−1 and distance s=12 m.
Let the final velocity be v.
We use the third equation of motion v2=u2+2as
So, v2=02+2×4×12
On solving we get v=2 ms−1.
Therefore, its velocity at the end of half a metre is 2 ms−1.