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Derivation of Position-Time Relation by Graphical Method

An object tak...

Question

An object takes $5 s e c$ to reach the ground from a height of $5 m$ on a planet. What is the value of $g$ on the planet?

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Solution

Here,
$u = 0 t = 5 s h = 5 m$
Using second equation of motion,
$s = u t + \frac{1}{2} a t^{2}$
$5 = (1 / 2) g \times 25$
$=> g = 0.4 m / s^{2}$

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Derivation of Position-Time Relation by Graphical Method

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