An object travels 10 s with uniform acceleration along a straight line path. During this period if the velocity of the object is increased from ${5 m s}^{- 1} t o {25 s}^{- 1}$ , then find the distance travelled by the body?

150

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

100

No worries! We‘ve got your back. Try BYJU‘S free classes today!

125

No worries! We‘ve got your back. Try BYJU‘S free classes today!

175

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $150$ m
Initial speed $u = 5 m / s$
Final speed $v = 25 m / s$
Time $t = 10 s$
Using $v = u + a t$
$∴$ $25 = 5 + a \times 10$
$⟹ a = 2 m / s^{2}$
Using $S = u t + \frac{1}{2} a t^{2}$
$S = 5 \times 10 + \frac{1}{2} \times 2 \times 10^{2} = 150 m$

Suggest Corrections

Similar questions

Q. The average velocity of a body moving with uniform acceleration travelling a distance

3.06 m

0.34 m/s

. If the change in velocity of the body is

0.18 m/s

during this time, its uniform acceleration is

Q. An object having a velocity 4.0 m/s is accelerated at the rate of 1.2 m/s² for 5.0 s. Find the distance travelled during the period of acceleration.

An object with an initial velocity of 12 m/s west experiences a constant acceleration of 4 m/ $s^{2}$ west for 3 second. During this time the object travels a distance of :

Q. An object starts moving with a velocity

6 m / s

and acceleration

105 m / s^{2}

after. What time will it acquire the velocity

15 m / s

? Find the distance traveled by the object in this time.

Q. An object is moving with uniform acceleration. Its velocity after 5s is 25 m\s and after 8s is 34m/s. Find the distance travelled by the object in 12th second.

Join BYJU'S Learning Program

An object travels 10 s with uniform acceleration along a straight line path. During this period if the velocity of the object is increased from 5 ms−1to 25 s−1, then find the distance travelled by the body?

The correct option is A 150 mInitial speed u=5 m/sFinal speed v=25 m/sTime t=10 sUsing v=u+at∴ 25=5+a×10⟹ a=2 m/s2Using S=ut+12at2S=5×10+12×2×102=150 m

An object travels 10 s with uniform acceleration along a straight line path. During this period if the velocity of the object is increased from ${5 m s}^{- 1} t o {25 s}^{- 1}$ , then find the distance travelled by the body?

The correct option is A $150$ m
Initial speed $u = 5 m / s$
Final speed $v = 25 m / s$
Time $t = 10 s$
Using $v = u + a t$
$∴$ $25 = 5 + a \times 10$
$⟹ a = 2 m / s^{2}$
Using $S = u t + \frac{1}{2} a t^{2}$
$S = 5 \times 10 + \frac{1}{2} \times 2 \times 10^{2} = 150 m$