An object weighs $10 N$ in air. When immersed fully in water, it weighs only $8 N$ . The weight of the liquid displaced by the object will be :

2 N

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8 N

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10 N

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12 N

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Solution

The correct option is A $2 N$
We know, according to archimedes principle,
Weight of Liquid displaced = Weight of body in air - Weight of body in liquid when immersed
Weight of liquid displaced = $10 - 8 = 2 N$

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An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be :

The correct option is A 2 NWe know, according to archimedes principle,Weight of Liquid displaced = Weight of body in air - Weight of body in liquid when immersedWeight of liquid displaced =10−8=2N

An object weighs $10 N$ in air. When immersed fully in water, it weighs only $8 N$ . The weight of the liquid displaced by the object will be :

The correct option is A $2 N$
We know, according to archimedes principle,
Weight of Liquid displaced = Weight of body in air - Weight of body in liquid when immersed
Weight of liquid displaced = $10 - 8 = 2 N$