An object weighs $840 g$ in air and $680 g$ when fully immersed in a liquid. What is the buoyant force on the object due to the liquid?

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Solution

$S t e p 1 : - G i v e n d a t a, W e i g h t o f a n o b j e c t i n a i r (W) = 840 g W e i g h t o f a n o b j e c t i n l i q u i d (W') = 680 g S t e p 2 : - T o f i n d : - B u o y a n t f o r c e S t e p 3 : - W e k n o w n t h a t, F o r m u l a - B u o y a n t f o r c e = W e i g h t o f l i q u i d d i s p l a c e d b y t h e o b j e c t F_{B} = (W - W') S t e p 4 : - S o l u t i o n, F_{B} = (840 - 680) F_{B} = 160 g o r 1.6 N S t e p 5 : - T h e a m o u n t o f l i q u i d d i s p l a c e d b y t h e o b j e c t i s 160 g o r 1.6 N w h i c h i s e q u a l t o t h e b u o y a n t f o r c e o n t h e o b j e c t d u e t o l i q u i d .$

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An object weighs 840g in air and 680g when fully immersed in a liquid. What is the buoyant force on the object due to the liquid?

An object weighs $840 g$ in air and $680 g$ when fully immersed in a liquid. What is the buoyant force on the object due to the liquid?