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Question

An object which is immersed in water experiences a buoyant force of 300gf.If density of fluid is 33g/cc and density of object is 43g/cc.
Find
1)weight of fluid displaced
2)mass of fluid displaced
3)volume of fluid displaced
4)volume of the object
5)mass of the object
6)weight of the object in air
7)weight of object in fluid

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Solution

5) Mass of the object m = 300g=0.3Kg.6) Weight of the object in air W = mg=0.300×9.8=2.94N.4) Volume of object V = massdensity=30043=6.98cc=6.98×10-6m33) Volume of the liquid displaced=volume of the object=6.98 cc.2) Mass of the liquid displaced ml=6.98×33=230.34g.1) Weight of the liquid displaced Wl = 0.23034×9.8=2.257N.7) Weight of the solid in the liquid= weight in air - weight of the liquid displaced Weight of the solid in the liquid=2.940-2.257=0.683N.

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