An objects has constant momentum of 2.45x10²kg m/s. Determine the momentum of the object if it’s mass decreases to 1/3 of its original value and applied forces causes the speed to increase to exactly four times of the original... The direction of the velocity remains the same...

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Solution

momentum(p)
= mass× velocity
= 245 kg m/s.
Now, mass decreases to 1/3 of its original value &
velocity becomes 4 times.
therefore ,
new momentum
p'=1/3 mass×4× velocity
=4×1/3×mass× velocity
=4/3×p
=4/3×245
= 326.666667kg m/s.

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An objects has constant momentum of 2.45x102 kg m/s. Determine the momentum of the object if it’s mass decreases to 1/3 of its original value and applied forces causes the speed to increase to exactly four times of the original... The direction of the velocity remains the same...

momentum(p) = mass× velocity = 245 kg m/s. Now, mass decreases to 1/3 of its original value & velocity becomes 4 times. therefore , new momentum p'=1/3 mass×4× velocity =4×1/3×mass× velocity =4/3×p =4/3×245 = 326.666667kg m/s.

An objects has constant momentum of 2.45x10²kg m/s. Determine the momentum of the object if it’s mass decreases to 1/3 of its original value and applied forces causes the speed to increase to exactly four times of the original... The direction of the velocity remains the same...

momentum(p)
= mass× velocity
= 245 kg m/s.
Now, mass decreases to 1/3 of its original value &
velocity becomes 4 times.
therefore ,
new momentum
p'=1/3 mass×4× velocity
=4×1/3×mass× velocity
=4/3×p
=4/3×245
= 326.666667kg m/s.